2x^2-7.9x+5=0

Solution for 2x^2-7.9x+5=0 equation:

2x^2-7.9x+5=0

a = 2; b = -7.9; c = +5;
Δ = b2-4ac
Δ = -7.92-4·2·5
Δ = 22.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.9)-\sqrt{22.41}}{2*2}=\frac{7.9-\sqrt{22.41}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.9)+\sqrt{22.41}}{2*2}=\frac{7.9+\sqrt{22.41}}{4}
$